{"resolved":true,"match_type":"uuid","source_type":"original_book","book_id":"38270854-596f-4a26-8183-db8c968c6020","title":"编码 隐匿在计算机软硬件背后的语言","author":null,"edition":null,"publisher":null,"year":null,"isbn":"9787121181184","requested_by":"printed_page","book":{"source_type":"original_book","book_id":"38270854-596f-4a26-8183-db8c968c6020","id":"38270854-596f-4a26-8183-db8c968c6020","uuid":"38270854-596f-4a26-8183-db8c968c6020","title":"编码 隐匿在计算机软硬件背后的语言","normalized_title":"编码隐匿在计算机软硬件背后的语言","author":null,"edition":null,"publisher":null,"year":null,"isbn":"9787121181184","isbns":["9787121181184","0123456789","6044921875","3039331000","0000000000","0000000000000"],"parsed":true,"ai_readable":true,"document_type":"book","page_count":438,"navigation_url":"https://workshop.closeclaw.top/ai/book/38270854-596f-4a26-8183-db8c968c6020","title_url":"https://workshop.closeclaw.top/ai/title/%E7%BC%96%E7%A0%81%20%E9%9A%90%E5%8C%BF%E5%9C%A8%E8%AE%A1%E7%AE%97%E6%9C%BA%E8%BD%AF%E7%A1%AC%E4%BB%B6%E8%83%8C%E5%90%8E%E7%9A%84%E8%AF%AD%E8%A8%80","fixed_page_url_template":"https://workshop.closeclaw.top/ai/book/38270854-596f-4a26-8183-db8c968c6020/page/{printed_page}","path_api_url_template":"https://workshop.closeclaw.top/api/ai/book/38270854-596f-4a26-8183-db8c968c6020/page/{printed_page}","read_url":"https://workshop.closeclaw.top/api/ai/read/38270854-596f-4a26-8183-db8c968c6020","page_url":"https://workshop.closeclaw.top/api/ai/books/38270854-596f-4a26-8183-db8c968c6020/page","search_url":"https://workshop.closeclaw.top/api/ai/books/38270854-596f-4a26-8183-db8c968c6020/search"},"page":{"printed_page":150,"pdf_page":166,"physical_index":166,"physical_index_base":0,"printed_page_status":"recognized","page_sha256":"0de892507dc58fab377c72de7b75d2d932d2336a5becf186fdd221755e7673b0"},"chapter":"编码隐匿在计算机软硬件背后的语言","content":"的答案：\n\n$$\n\\frac { - 2 5 3 } { 7 7 }\n$$\n\n如果希望求解这个问题而不使用借位的话，就要采用与之前稍微不同的方法。首先要像前面一样，用999减去减数253，计算出对9的补数：\n\n$$\n\\frac { - 2 5 3 } { 7 4 6 }\n$$\n\n把该数对9的补数与被减数相加：\n\n$$\n\\frac { 1 7 6 } { 9 2 2 }\n$$\n\n在前面的例子中，下一步应该加1，并减去1000来得到最终结果。但是在这里，这种方法并不适用。因为你会遇到923减去1000的情况，这又导致了借位。\n\n由于我们之前已经加了999，这里再减去999：\n\n$$\n\\frac { - 9 9 9 } { 7 7 9 }\n$$\n\n到这里，我们会意识到这个问题的结果是负数，因此需要将减数与被减数交换，用999减去922。这里没有用到借位，结果与我们期望的相同：\n\n$$\n\\frac { - 9 9 9 } { - 7 7 }\n$$\n\n同样的技巧可以用于二进制数中，而且实际上这要比十进制数简单。让我们一起来看看该如何操作。\n\n原来的减法题目是：\n\n编码—隐匿在计算机软硬件背后的语言\n\n150","previous_page":149,"next_page":151}