{"resolved":true,"match_type":"uuid","source_type":"original_book","book_id":"38270854-596f-4a26-8183-db8c968c6020","title":"编码 隐匿在计算机软硬件背后的语言","author":null,"edition":null,"publisher":null,"year":null,"isbn":"9787121181184","requested_by":"printed_page","book":{"source_type":"original_book","book_id":"38270854-596f-4a26-8183-db8c968c6020","id":"38270854-596f-4a26-8183-db8c968c6020","uuid":"38270854-596f-4a26-8183-db8c968c6020","title":"编码 隐匿在计算机软硬件背后的语言","normalized_title":"编码隐匿在计算机软硬件背后的语言","author":null,"edition":null,"publisher":null,"year":null,"isbn":"9787121181184","isbns":["9787121181184","0123456789","6044921875","3039331000","0000000000","0000000000000"],"parsed":true,"ai_readable":true,"document_type":"book","page_count":438,"navigation_url":"https://workshop.closeclaw.top/ai/book/38270854-596f-4a26-8183-db8c968c6020","title_url":"https://workshop.closeclaw.top/ai/title/%E7%BC%96%E7%A0%81%20%E9%9A%90%E5%8C%BF%E5%9C%A8%E8%AE%A1%E7%AE%97%E6%9C%BA%E8%BD%AF%E7%A1%AC%E4%BB%B6%E8%83%8C%E5%90%8E%E7%9A%84%E8%AF%AD%E8%A8%80","fixed_page_url_template":"https://workshop.closeclaw.top/ai/book/38270854-596f-4a26-8183-db8c968c6020/page/{printed_page}","path_api_url_template":"https://workshop.closeclaw.top/api/ai/book/38270854-596f-4a26-8183-db8c968c6020/page/{printed_page}","read_url":"https://workshop.closeclaw.top/api/ai/read/38270854-596f-4a26-8183-db8c968c6020","page_url":"https://workshop.closeclaw.top/api/ai/books/38270854-596f-4a26-8183-db8c968c6020/page","search_url":"https://workshop.closeclaw.top/api/ai/books/38270854-596f-4a26-8183-db8c968c6020/search"},"page":{"printed_page":202,"pdf_page":218,"physical_index":218,"physical_index_base":0,"printed_page_status":"recognized","page_sha256":"9422ba54b4ce1fb4ed147530cf53e55feb8fa636b4fac93231cd6597d2f3bf55"},"chapter":"编码隐匿在计算机软硬件背后的语言","content":"8-1选择器主要组成部件为：三个反向器、八个4端口输入与门、一个8端口输入或门，系统的组织结构如下图所示。\n\n这个电路看上去线路密布，要理解它是如何工作的，最好方式就是一起来看一个例子。假设S2初始化为1，S1初始化为0，So初始化为 $1 _ { \\circ }$ 从顶部开始的第6个与门的输入由 ${ \\bf S } _ { 0 }$ 、 $\\overline { { \\mathbf { S } } } _ { 1 }$ 、 ${ \\bf S } _ { 2 }$ 组成，初始状态下它们全为1。其余与门的这三项输入数据都与第6个与门不尽相同，这使得其余与门输出全部为 $\\mathbf { 0 } _ { \\circ }$ 若 $\\mathbf { D } _ { 5 }$ 变为0意味着第6个与门输出为0；反之第 ${ \\bf 6 }$ 个与门输出则为 $\\mathbf { l _ { \\varphi _ { \\circ } } }$ 对最右边的或门也可以按照同样的方式理解。我们可以总结出下面这个结论：若选择端为101，则数据输出端与 $\\mathbf { D } _ { 5 }$ 的输出保持一致。\n\n编码——隐匿在计算机软硬件背后的语言\n\n202","previous_page":201,"next_page":203}