{"resolved":true,"match_type":"uuid","source_type":"original_book","book_id":"38270854-596f-4a26-8183-db8c968c6020","title":"编码 隐匿在计算机软硬件背后的语言","author":null,"edition":null,"publisher":null,"year":null,"isbn":"9787121181184","requested_by":"printed_page","book":{"source_type":"original_book","book_id":"38270854-596f-4a26-8183-db8c968c6020","id":"38270854-596f-4a26-8183-db8c968c6020","uuid":"38270854-596f-4a26-8183-db8c968c6020","title":"编码 隐匿在计算机软硬件背后的语言","normalized_title":"编码隐匿在计算机软硬件背后的语言","author":null,"edition":null,"publisher":null,"year":null,"isbn":"9787121181184","isbns":["9787121181184","0123456789","6044921875","3039331000","0000000000","0000000000000"],"parsed":true,"ai_readable":true,"document_type":"book","page_count":438,"navigation_url":"https://workshop.closeclaw.top/ai/book/38270854-596f-4a26-8183-db8c968c6020","title_url":"https://workshop.closeclaw.top/ai/title/%E7%BC%96%E7%A0%81%20%E9%9A%90%E5%8C%BF%E5%9C%A8%E8%AE%A1%E7%AE%97%E6%9C%BA%E8%BD%AF%E7%A1%AC%E4%BB%B6%E8%83%8C%E5%90%8E%E7%9A%84%E8%AF%AD%E8%A8%80","fixed_page_url_template":"https://workshop.closeclaw.top/ai/book/38270854-596f-4a26-8183-db8c968c6020/page/{printed_page}","path_api_url_template":"https://workshop.closeclaw.top/api/ai/book/38270854-596f-4a26-8183-db8c968c6020/page/{printed_page}","read_url":"https://workshop.closeclaw.top/api/ai/read/38270854-596f-4a26-8183-db8c968c6020","page_url":"https://workshop.closeclaw.top/api/ai/books/38270854-596f-4a26-8183-db8c968c6020/page","search_url":"https://workshop.closeclaw.top/api/ai/books/38270854-596f-4a26-8183-db8c968c6020/search"},"page":{"printed_page":227,"pdf_page":243,"physical_index":243,"physical_index_base":0,"printed_page_status":"recognized","page_sha256":"fe5a1f2a413251b5ebda859171bccda601b0e0ccd9cb34434b1d74b496ec0451"},"chapter":"编码隐匿在计算机软硬件背后的语言","content":"列中的代码（操作码）和数据（操作数）完成该运算。\n\nLoad操作完成之后，累加器中的值更新为56h，加法操作完成后累加器中的值为56h与2Ah的和，即80h。Subtract操作使数据RAM阵列的下个值（38h）按位取反，得到C7h。当加法器的进位输入置1时，取反得到C7h，然后使其与80h相加：\n\n$$\n\\begin{array} { r } { \\mathrm { C ^ { \\prime } / f _ { 1 } } } \\\\ { \\mathrm { ~ } } \\\\ { \\mathrm { ~ } } \\\\ { \\mathrm { ~ \\mathfrak { f } ^ { \\prime } ~ } } \\\\ { \\mathrm { ~ \\mathfrak { f } ^ { \\prime } ~ } } \\\\ { \\mathrm { ~ \\mathfrak { f } ^ { \\prime } ~ } } \\end{array}\n$$\n\n最后的结果是48h。（有十进制中，80加4再减人56等十12)\n\n过有自没有找到台活的解决归法宿中题，加法器技连接到工的同有蟲备的商度只有8位。以前提出过的个解决办法是把两午8位加法器（具他的大部分设备也用两个）连在一起，构成↑16位的设备。\n\n但还有代价更小的解决办法，假如你想把两个16位的数相加，比如，\n\n$$\n\\begin{array} { c } { { 7 6 \\mathrm { A B h } } } \\\\ { { } } \\\\ { { + 2 3 2 \\mathrm { C h } } } \\\\ { { \\ } } \\end{array}\n$$\n\n这种16位的加法先单独处理最石边的字节（通常称之为低字节）：\n\n$$\n\\begin{array} { r } { \\mathbf { A B h } } \\\\ { \\frac { + 2 \\mathbf { C h } } { \\mathbf { D } / \\mathbf { h } } } \\end{array}\n$$\n\n然后再计算最左边的字节，即高字节的和：\n\n17自动操作\n\n227","previous_page":226,"next_page":228}