{"resolved":true,"match_type":"uuid","source_type":"original_book","book_id":"88efeb70-2043-4122-a461-fbf8384bb0fc","title":"形而上学","author":null,"edition":null,"publisher":null,"year":null,"isbn":"7100011361","requested_by":"printed_page","book":{"source_type":"original_book","book_id":"88efeb70-2043-4122-a461-fbf8384bb0fc","id":"88efeb70-2043-4122-a461-fbf8384bb0fc","uuid":"88efeb70-2043-4122-a461-fbf8384bb0fc","title":"形而上学","normalized_title":"形而上学","author":null,"edition":null,"publisher":null,"year":null,"isbn":"7100011361","isbns":["7100011361"],"parsed":true,"ai_readable":true,"document_type":"book","page_count":383,"navigation_url":"https://workshop.closeclaw.top/ai/book/88efeb70-2043-4122-a461-fbf8384bb0fc","title_url":"https://workshop.closeclaw.top/ai/title/%E5%BD%A2%E8%80%8C%E4%B8%8A%E5%AD%A6","fixed_page_url_template":"https://workshop.closeclaw.top/ai/book/88efeb70-2043-4122-a461-fbf8384bb0fc/page/{printed_page}","path_api_url_template":"https://workshop.closeclaw.top/api/ai/book/88efeb70-2043-4122-a461-fbf8384bb0fc/page/{printed_page}","read_url":"https://workshop.closeclaw.top/api/ai/read/88efeb70-2043-4122-a461-fbf8384bb0fc","page_url":"https://workshop.closeclaw.top/api/ai/books/88efeb70-2043-4122-a461-fbf8384bb0fc/page","search_url":"https://workshop.closeclaw.top/api/ai/books/88efeb70-2043-4122-a461-fbf8384bb0fc/search"},"page":{"printed_page":186,"pdf_page":190,"physical_index":190,"physical_index_base":0,"printed_page_status":"recognized","page_sha256":"1eabf6ad7818663c576925185b1a60c75c07c846ef00bb112a6136dab0fec5b6"},"chapter":"形而上学","content":"些与三角一边的平行綫划出来，凡見到图的人就会明白。①何以半圓形内的角无論在何处均成一直角？假如兩綫为底綫与中心垂直的一綫，三綫相等一人們倘已知前項几何定例，結論就可以一瞥30而知了。②所以明显地，潜在的图解因实行分划而发見；理由是几何学者的思想是一个“实現”，由实现酝成为潛能；迨进行繪划而大家得以明曉图意，虽則这末一实現是后于相应的潛能；但这潛能却35是由那个几何学者的前一实現发展起来的。\n\n1051b “是”与“非是”这兩名詞最先应用于有关范疇，其次有关这些范疇的潛能或实現，或是它們的无潛能与非实現，第三則应用于真实与虚假。真假的問題依事物对象的是否联合或分离而定，若对象相合者認为相合，相离者認为相离就得其真实；反之，以相离者5为合，以相合者为离，那就弄錯了。这样，所謂真假何时存在，何时又不存在呢？我們必需考虑这些名詞的实义。\n\n拜不因为我們說你臉是白，所以你臉才白；只因为你臉是白，10所以我們这样說才算說得对。于是，假如有些事物常合而不能离，另些事物常离而不能合，再有些事物是可离亦可合，則合而为一者i\n\n①在C点上划CE綫与AB平行。\n\n$$\n\\begin{array} { r l } { \\cdot \\ } & { \\angle A B C = \\angle E C D , } \\\\ & { \\angle B A C = \\angle A C E , } \\\\ { \\therefore } & { \\angle A C B + \\angle B A C + \\angle A B C } \\\\ & { = \\angle A C B + \\angle A C E + \\angle E C D } \\\\ & { = \\mathbb { E H H } \\mathbb { E } \\mathbb { 1 } } \\end{array}\n$$\n\n②ED垂直綫与 BD 及 DC 相等。\n\n$$\n\\begin{array} { r l } { \\cdot } & { \\angle A C E = \\angle A B E } \\\\ & { \\angle A C B + \\angle A B C } \\\\ & { \\qquad = \\angle E B C + \\angle E C B , } \\\\ { \\therefore } & { \\angle B E C = \\angle B A C = \\angle \\sharp \\sharp _ { \\bullet } } \\end{array}\n$$\n\n③几何图解例这一节似可移屬第八章(二)1049b18—105032。\n\n10\n\n1051b\n\n186","previous_page":185,"next_page":187}