{"resolved":true,"match_type":"uuid","source_type":"original_book","book_id":"dde4e586-1def-4457-8ec5-0287b0b0511d","title":"认知 人行为背后的思维与智能","author":null,"edition":null,"publisher":null,"year":null,"isbn":"9787300273921","requested_by":"printed_page","book":{"source_type":"original_book","book_id":"dde4e586-1def-4457-8ec5-0287b0b0511d","id":"dde4e586-1def-4457-8ec5-0287b0b0511d","uuid":"dde4e586-1def-4457-8ec5-0287b0b0511d","title":"认知 人行为背后的思维与智能","normalized_title":"认知人行为背后的思维与智能","author":null,"edition":null,"publisher":null,"year":null,"isbn":"9787300273921","isbns":["9787300273921"],"parsed":true,"ai_readable":true,"document_type":"book","page_count":290,"navigation_url":"https://workshop.closeclaw.top/ai/book/dde4e586-1def-4457-8ec5-0287b0b0511d","title_url":"https://workshop.closeclaw.top/ai/title/%E8%AE%A4%E7%9F%A5%20%E4%BA%BA%E8%A1%8C%E4%B8%BA%E8%83%8C%E5%90%8E%E7%9A%84%E6%80%9D%E7%BB%B4%E4%B8%8E%E6%99%BA%E8%83%BD","fixed_page_url_template":"https://workshop.closeclaw.top/ai/book/dde4e586-1def-4457-8ec5-0287b0b0511d/page/{printed_page}","path_api_url_template":"https://workshop.closeclaw.top/api/ai/book/dde4e586-1def-4457-8ec5-0287b0b0511d/page/{printed_page}","read_url":"https://workshop.closeclaw.top/api/ai/read/dde4e586-1def-4457-8ec5-0287b0b0511d","page_url":"https://workshop.closeclaw.top/api/ai/books/dde4e586-1def-4457-8ec5-0287b0b0511d/page","search_url":"https://workshop.closeclaw.top/api/ai/books/dde4e586-1def-4457-8ec5-0287b0b0511d/search"},"page":{"printed_page":138,"pdf_page":149,"physical_index":149,"physical_index_base":0,"printed_page_status":"recognized","page_sha256":"13f0482ef2c30b2f1cc688fa7c4f710a7e25ae9527ecb6d01b8b6a52b37cc209"},"chapter":"第四章口语记录分析","content":"附录Ⅱ解决物理问题的口语记录示例\n\n题目：现有氮气流过一条等截面管道。氮气流入管道时的温度为华氏40度，压强为200磅/平方英寸。流出管道时压强为一个大气压，温度为华氏一210度。假设流量为100磅/分，问：在这过程中，氮气向外散发了多少热量？\n\n口语记录：\n\n1. 好，我得先定出一个系统来。\n\n2. 呶，管道就可以作为一个系统。\n\n3. 那么，我就把它画出来。\n\n4. 在上面写上第一定律：\n\n5. Q加W；等于m乘上h2与 $\\mathrm { h _ { i } }$ 之差。\n\n6. 在这里我忽略了动能和势能的变化。\n\n7. 我想这样忽略一下倒还是挺不赖的。\n\n8. 好吧，问题问的是氮气向外散发了多少热量。\n\n9. 那就是这儿的Q项了。\n\n10.既然这里仅是一条管道，那也就无所谓什么轴输出功。\n\n11. 这样，W就等于零。\n\n12. 那么，Q就等于m乘上 $\\mathrm { h _ { 2 } }$ 减 $\\mathrm { h } _ { 1 }$\n\n认知\n\n138","previous_page":137,"next_page":139}